(c+4)(c+7)=c^2=11c+28

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Solution for (c+4)(c+7)=c^2=11c+28 equation:



(c+4)(c+7)=c^2=11c+28
We move all terms to the left:
(c+4)(c+7)-(c^2)=0
determiningTheFunctionDomain -c^2+(c+4)(c+7)=0
We add all the numbers together, and all the variables
-1c^2+(c+4)(c+7)=0
We multiply parentheses ..
-1c^2+(+c^2+7c+4c+28)=0
We get rid of parentheses
-1c^2+c^2+7c+4c+28=0
We add all the numbers together, and all the variables
11c+28=0
We move all terms containing c to the left, all other terms to the right
11c=-28
c=-28/11
c=-2+6/11

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